蛮多的地方可以 看你自己喜欢 me stretchest地 . constant panorama址 https://abco89.com?huoy ······································ 过点(0,1)设函数为y=ax²+bx+1 又过点(2,4),(3,10)得4a+2b+1=4 9a+3b+1=10 得a=3/2 b=-3/2 所以y=3/2x²-3/2x+1又过点(0,1),得a=-1/8 已知图像顶点,可设y=a(x-8)²+9
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
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