链接：n点H这X打T开l . 因为y=(x^2-x+3)/(x^2-x-1)所以(x^2-x+3)=y(x^2-x-1)(y-1)x^2+(1-y)x-y-3=01. y=1时,-4=0矛盾,不行!2. y≠1Δ=(1-y)^2-4*(y-1)(-y-3)=(y-1)(y-1+4y+12)=(y-1)(5y+11)>=0所以值域为:y<=-11/5或y>1.
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
娱乐八卦2022-05-31
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